u^2-3u+2/3u^2-12

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Solution for u^2-3u+2/3u^2-12 equation: 


u in (-oo:+oo)

u^2+(2/3)*u^2-(3*u)-12 = 0

u^2+(2/3)*u^2-3*u-12 = 0

5/3*u^2-3*u-12 = 0

DELTA = (-3)^2-(-12*5/3*4)

DELTA = 89

DELTA > 0

u = (89^(1/2)+3)/(5/3*2) or u = (3-89^(1/2))/(5/3*2)

u = 3/10*(89^(1/2)+3) or u = 3/10*(3-89^(1/2))

u in { 3/10*(3-89^(1/2)), 3/10*(89^(1/2)+3) }

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